0.14x^2+x-34.59=0

Solution for 0.14x^2+x-34.59=0 equation:

0.14x^2+x-34.59=0

a = 0.14; b = 1; c = -34.59;
Δ = b2-4ac
Δ = 12-4·0.14·(-34.59)
Δ = 20.3704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{20.3704}}{2*0.14}=\frac{-1-\sqrt{20.3704}}{0.28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{20.3704}}{2*0.14}=\frac{-1+\sqrt{20.3704}}{0.28}
$